(x^2-2yz^2-y^2)(y^2+x)=0

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Solution for (x^2-2yz^2-y^2)(y^2+x)=0 equation: 


Simplifying
(x2 + -2yz2 + -1y2)(y2 + x) = 0

Reorder the terms:
(x2 + -2yz2 + -1y2)(x + y2) = 0

Multiply (x2 + -2yz2 + -1y2) * (x + y2)
(x2(x + y2) + -2yz2 * (x + y2) + -1y2 * (x + y2)) = 0
((x * x2 + y2 * x2) + -2yz2 * (x + y2) + -1y2 * (x + y2)) = 0

Reorder the terms:
((x2y2 + x3) + -2yz2 * (x + y2) + -1y2 * (x + y2)) = 0
((x2y2 + x3) + -2yz2 * (x + y2) + -1y2 * (x + y2)) = 0
(x2y2 + x3 + (x * -2yz2 + y2 * -2yz2) + -1y2 * (x + y2)) = 0
(x2y2 + x3 + (-2xyz2 + -2y3z2) + -1y2 * (x + y2)) = 0
(x2y2 + x3 + -2xyz2 + -2y3z2 + (x * -1y2 + y2 * -1y2)) = 0
(x2y2 + x3 + -2xyz2 + -2y3z2 + (-1xy2 + -1y4)) = 0

Reorder the terms:
(-2xyz2 + -1xy2 + x2y2 + x3 + -2y3z2 + -1y4) = 0
(-2xyz2 + -1xy2 + x2y2 + x3 + -2y3z2 + -1y4) = 0

Solving
-2xyz2 + -1xy2 + x2y2 + x3 + -2y3z2 + -1y4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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